Solutions-Class-12-Chemistry-Chapter-10-Halogen Derivatives-Maharashtra Board

Halogen Derivatives

Maharashtra Board-Class-12-Chemistry-Chapter-10

Solutions

Question 1. Choose the most correct option.

(i) The correct order of increasing reactivity of C-X bond towards nucleophile in the following compounds is

(a) I < II < III < IV

(b) II < I < III < IV

(c) III < IV < II < I

(d) IV < III < I < II

Answer :

(d) IV < III < I < II

Explanation:

Alkyl halides are more reactive than aryl halides. This is because of the partial double bond character between the benzene ring and the halogen. Further, in alkyl halides, the greater the stability of carbocation formed, the more would be the reactivity. Thus, the tertiary halide is more reactive. Nitro group which is electron-withdrawing increases the reactivity of aryl halide.

(ii) CH3-CH=CH \(\underrightarrow{Hi/Peroxide}\)

The major product of the above reaction is,

Answer :

(b) CH3-CH2-CH2I

(iii) Which of the following is likely to undergo racemization during alkaline hydrolysis ?

(a) Only I

(b) Only II

(c) II and IV

(d) Only IV

Answer :

(a) Only I

(iv) The best method for preparation of alkyl fluorides is

(a) Finkelstein reaction

(b) Swartz reaction

(c) Free radical fluorination

(d) Sandmeyer's reaction

Answer :

(b) Swartz reaction

(v) Identify the chiral molecule from the following.

(a) 1-Bromobutane

(b) 1,1- Dibromobutane

(c) 2,3- Dibromobutane

(d) 2-Bromobutane

Answer :

(d) 2-Bromobutane

(vi) An alkyl chloride on Wurtz reaction gives 2,2,5,5-tetramethylhexane. The same alkyl chloride on reduction with zinc-copper couple in alcohol give hydrocarbon with molecular formula C5H12. What is the structure of alkyl chloride

Answer :

(vii) Butanenitrile may be prepared by heating

(a) propanol with KCN

(b) butanol with KCN

(c) n-butyl chloride with KCN

(d) n-propyl chloride with KCN

Answer :

(d) n-propyl chloride with KCN

(viii) Choose the compound from the following that will react fastest by SN1 mechanism.

(a) 1-iodobutane

(b) 1-iodopropane

(c) 2-iodo-2 methylbutane

(d) 2-iodo-3-methylbutane

Answer :

(c) 2-iodo-2 methylbutane

(ix)

The product 'B' in the above reaction sequence is,

Answer :

 

(x) Which of the following is used as source of dichlorocarbene

(a) tetrachloromethane

(b) chloroform

(c) iodoform

(d) DDT

Answer :

(b) chloroform

Question 2. Do as directed.

(i) Write IUPAC name of the following compounds

Answer :

(a) 4-Bromo-3, 4 dimethyl but-2-ene

(b) 2-Chloro-3-methyl pentane

(c) 1-Chloro-4-ethyl cyclohexane

(d) 1,4-Dichloro-2-methyl benzene

(ii) Write structure and IUPAC name of the major product in each of the following reaction.

Answer :

(iii) Identify chiral molecule/s from the following.

Answer :

(iv) Which one compound from the following pairs would undergo SN2 faster from the?

Answer :

(a) Since is a primary halide it undergoes SN2 reaction faster than

(b) Since iodine is a better leaving group than chloride, 1-iodopropane (CH3CH2CH2I) undergoes SN2 reaction faster than 1-chloropropane (CH3CH2CH2Cl).

(v) Complete the following reactions giving major product.

Answer :

(b)

Answer :

(c)

Answer :

(d)

Answer :

(vi) Name the reagent used to bring about the following conversions.

(a) Bromoethane to ethoxyethane

(b) 1-Chloropropane to 1 nitropropane

(c) Ethyl bromide to ethyl isocyanide

(d) Chlorobenzene to biphenyl

Answer :

(vii) Arrange the following in the increase order of boiling points

(a) 1-Bromopropane  (b) 2- Bromopropane  (c) 1- Bromobutane  (d) 1-Bromo-2-methylpropane

Answer :

2-Bromopropane < 1-Bromopropane < 1-Bromo-2-methylpropane < 1-Bromo butane.

(viii) Match the pairs.

Column I Column II
i. vinyl halide
b. CH2=CH-CH2X ii. alkyl halide
c. CH2=CH-X iii. allyl halide
iv. benzyl halide
v. aryl halide

Answer :

Column I Column II
i. vinyl halide
b. CH2=CH-CH2X iii. allyl halide
c. CH2=CH-X i. vinyl halide

Question 3. Give reasons

(i) Haloarenes are less reactive than halo alkanes.

Answer :

  • The low reactivity of aryl halides is due to resonance effect and sp2 hybrid state of carbon to which halogen atom is attached.
  • In aryl halides, one of the lone pairs of electrons on halogen atom is in conjugation with π-electrons of the ring. Due to resonance, the C-X bond acquires partial double bond character. Thus, the C-X bond in haloarenes is stronger and shorter than haloalkanes. Hence, it is difficult to break C-X bond in haloarenes. (e.g. C-CI bond length in chlorobenzene is 169 pm as compared to C-CI bond length in alkyl chloride which is 178 pm).

Therefore, haloarenes are less reactive than haloalkanes.

(ii) Alkyl halides though polar are immiscible with water.

Answer :

  • Alkyl halides cannot form hydrogen bonds with water.
  • In addition to this, the attraction between alkyl halide molecules is stronger than the attraction between alkyl halide and water.

Hence, alkyl halides though moderately polar are immiscible with water.

(iii) Reactions involving Grignard reagent must be carried out under anhydrous condition.

Answer :

  • Grignard reagent (R Mg X) is an organometallic compound. The carbon-magnesium bond is highly polar and magnesium halogen bond is in ionic in nature. Grignard reagent is highly reactive.
  • The reactions of Grignard reagent are carried out in dry conditions because traces of moisture may spoil the reaction and Grignard reagent reacts with water to produce alkane. Hence, reactions involving Grignard reagent must be carried out under anhydrous condition.

(iv) Alkyl halides are generally not prepared by free radical halogenation of alkanes.

Answer :

  • Free radical halogenation of alkane gives a mixture of all different possible Monohaloalkanes as well as polyhalogen alkanes.
  • In this method, by changing the quantity of halogen the desired product can be made to predominate over the other products. Hence, alkyl halides are generally not prepared by free radical halogenation of alkane.

Question 4. Distinguish between - SN1 and SN2 mechanism of substitution reaction?

Answer :

Factor SN1 SN2
Number of steps Two steps One step
Molecularity/Order Unimolecular/1st order Bimolecular/2nd order
Reaction rate Depends upon concentration of one reacting species Depends upon concentration of two reacting species
Attack of a nucleophile Back side attack and front side attack on a substrate with equal probability Only back side attack on a substrate
Transition state Two steps, two transition states One step, one transition state
Type of substrate Mainly tertiary (3°) substrate Mainly primary (1°) substrate
Stereochemistry 50% inversion and 50% retention of configuration 100% inversion of configuration
Enantiomer Forms racemic mixture Forms opposite enantiomer
Solvent Polar solvent favourable Nonpolar solvent favourable
Energy of activation Two values of energies of activation One value of energy activation
Intermediate Carbocation intermediates No intermediate
Nucleophile Weak nucleophile favourable Strong nucleophile favourable
Order of reactivity in alkyl halides Tertiary > Secondary > Primary Primary > Secondary > Tertiary

Question 5. Explain - Optical isomerism in 2-chlorobutane.

Answer :

  • The stereoisomerism in which the isomers have different spatial arrangements of groups/atoms around a chiral atom is called optical isomerism.
  • 2-chlorobutane has one chiral carbon atom. The spatial arrangement of the four different groups around the chiral atom is different.

  • Two different arrangements of these groups around the carbon atom are possible as shown in the figure. Hence, it exists as a pair of enantiomers. The two enantiomers are mirror images of each other and are not superimposable.
  • One of the enantiomers will rotate the plane of plane-polarized light to the left hand side and is called the laevorotatory isomer (l-isomer). The other enantiomer will rotate the plane of plane-polarized light to the right hand side and is called the dextrorotatory isomer (d-isomer).
  • Equimolar mixture of the d- and the l-isomers is optically inactive and is called the racemic mixture or the racemate (dl-mixture). The optical inactivity of the racemic mixture is due to external compensation.

Question 6. Convert the following.

(i) Propene to propan-1-ol

Answer :

(ii) Benzyl alcohol to benzyl cyanide

Answer :

(iii) Ethanol to propane nitrile

Answer :

(iv) But-1-ene to n-butyl iodide

Answer :

(v) 2-Chloropropane to propan-1-ol

Answer :

(vi) tert-Butyl bromide to isobutyl bromide

Answer :

(vii) Aniline to chlorobenzene

Answer :

 

(viii) Propene to 1-nitropropane

Answer :

 

Question 7. Answer the following

(i) HCl is added to a hydrocarbon 'A' (C4H8) to give a compound 'B' which on hydrolysis with aqueous alkali forms tertiary alcohol 'C' (C4H10O). Identify 'A', 'B' and 'C'.

Answer :

(ii) Complete the following reaction sequences by writing the structural formulae of the organic compounds 'A', 'B' and 'C' .

Answer :

(a)

(b)

(iii) Observe the following and answer the questions given below.

(a) Name the type of halogen derivative

(b) Comment on the bond length of C-X bond in it

(c) Can react by SN1 mechanism?

Justify your answer.

Answer :

(1) Vinyl halide

(2) C-X bond length shorter in vinyl halide than alkyl halide. Vinyl halide has partial double bond character due to resonance.

In vinyl halide, carbon is sp2-hybridized. The bond is shorter and stronger and the molecule is more stable.

(3) Yes, It reacts by SN1 mechanism. SN1 mechanism involves formation of carbocation intermediate. The vinylic carbocation intermediate formed is resonance stabilized, hence SN1 mechanism is favoured.

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